1. What is the Electric Motor Power and Torque Equation?

The electric motor power and torque equation (P = T × ω) describes the relationship between mechanical power, torque, and angular velocity. It is fundamental in electrical engineering and motor design for calculating the power output of rotating machinery.

2. How Does the Calculator Work?

The calculator uses the power and torque equation:

Where:

• \( P \) — Power in watts (W)
• \( T \) — Torque in newton-meters (Nm)
• \( \omega \) — Angular velocity in radians per second (rad/s)

Explanation: This equation shows that mechanical power is the product of torque and angular velocity. It applies to all rotating electrical machines including motors and generators.

3. Importance of Power and Torque Calculation

Details: Accurate power and torque calculations are essential for motor selection, system design, efficiency analysis, and ensuring proper matching between motors and their mechanical loads in various applications.

4. Using the Calculator

Tips: Enter torque in newton-meters and angular velocity in radians per second. Both values must be positive numbers greater than zero for valid calculations.

5. Frequently Asked Questions (FAQ)

Q1: What is the difference between torque and power?
A: Torque is a rotational force, while power is the rate at which work is done. Power combines both torque and rotational speed.

Q2: How do I convert RPM to rad/s?
A: Multiply RPM by 2π/60 (approximately 0.10472) to convert to rad/s. For example, 1000 RPM = 1000 × (2π/60) ≈ 104.72 rad/s.

Q3: What are typical torque values for electric motors?
A: Torque values vary widely by motor type and size, from fractional Nm for small motors to thousands of Nm for large industrial motors.

Q4: Does this equation apply to both AC and DC motors?
A: Yes, the fundamental relationship P = T × ω applies to all types of rotating electric machines, regardless of whether they are AC or DC.

Q5: How does efficiency affect the calculation?
A: This equation calculates mechanical output power. Electrical input power would be higher due to losses from efficiency factors like copper losses, iron losses, and friction.