1. What is Hydraulic Motor Displacement?

Hydraulic motor displacement refers to the volume of fluid required to make the motor output shaft complete one revolution. It is a critical parameter that determines the motor's torque output and speed characteristics in hydraulic systems.

2. How Does the Calculator Work?

The calculator uses the hydraulic motor displacement formula:

Where:

• \( V \) — Displacement (cm³/rev)
• \( Q \) — Flow rate (L/min)
• \( N \) — Rotational speed (rpm)

Explanation: The formula calculates the volume of hydraulic fluid needed per revolution based on the flow rate and motor speed, with the 1000 multiplier converting liters to cubic centimeters.

3. Importance of Displacement Calculation

Details: Accurate displacement calculation is essential for proper hydraulic system design, motor selection, torque estimation, and ensuring optimal system performance and efficiency.

4. Using the Calculator

Tips: Enter flow rate in liters per minute (L/min) and motor speed in revolutions per minute (rpm). Both values must be positive numbers greater than zero for accurate calculation.

5. Frequently Asked Questions (FAQ)

Q1: What is the relationship between displacement and torque?
A: Higher displacement motors generally produce higher torque at the same pressure, as torque is directly proportional to displacement.

Q2: How does displacement affect motor speed?
A: For a given flow rate, motors with smaller displacement will rotate faster, while larger displacement motors will rotate slower but with more torque.

Q3: What are typical displacement values for hydraulic motors?
A: Displacement values can range from a few cm³/rev for small motors to several thousand cm³/rev for large industrial applications.

Q4: Can this formula be used for hydraulic pumps as well?
A: Yes, the same principle applies to hydraulic pumps, where displacement represents the volume of fluid pumped per revolution.

Q5: What factors can affect the accuracy of this calculation?
A: System efficiency, fluid viscosity, pressure variations, and mechanical losses can affect the actual performance compared to theoretical calculations.